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Popular >

6|-f+3|+7>7

Solution

6 ∣ - f + 3 ∣ + 7 > 7

Solution

f < 3 or f > 3

+1

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

6 ∣ - f + 3 ∣ + 7 > 7

Subtract

7

from both sides

6 ∣ - f + 3 ∣ + 7 - 7 > 7 - 7

Simplify

6 ∣ - f + 3 ∣ > 0

Divide both sides by

6

∣ - f + 3 ∣ > 0

Apply absolute rule: If

∣ u ∣ > 0

then

u < 0

or

u > 0

- f + 3 < 0 or - f + 3 > 0

- f + 3 < 0 or - f + 3 > 0

f < 3 or f > 3

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(x^{\frac{1}{3}})^{2}

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(- 8) \frac{v}{- 8} > 2 (- 8)

15 x^{2} - 4 = 17 x

2 - \frac{1}{2} n = 3 n + 16

simplify 3.643*10^{-1}simplify

3.643 \cdot 1 0^{- 1}

Frequently Asked Questions (FAQ)

What is 6|-f+3|+7>7 ?
The solution to 6|-f+3|+7>7 is f<3\lor f>3