What are the solutions to the equation x^2-10x+7=0 ?

The solutions to the equation x^2-10x+7=0 are x=5+3sqrt(2),x=5-3sqrt(2)

Find the zeros of x^2-10x+7=0

The zeros of x^2-10x+7=0 are x=5+3sqrt(2),x=5-3sqrt(2)

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x^{2} - 10 x + 7 = 0

x = 5 + 32, x = 5 - 32

Solution steps

x^{2} - 10 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 7 = 62

x_{1, 2} = \frac{- ( - 10 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6 2}{2 \cdot 1} : 5 + 32

x = \frac{- ( - 10 ) - 6 2}{2 \cdot 1} : 5 - 32

The solutions to the quadratic equation are:

x = 5 + 32, x = 5 - 32

1 = \frac{x + 3}{6}

\frac{4000}{4 \cdot 1 0 ^{- 5}}

\frac{2 x}{x - 2} < 3

27 \leq 7 x + 6

- 8 c = 64

What are the solutions to the equation x^2-10x+7=0 ?
The solutions to the equation x^2-10x+7=0 are x=5+3sqrt(2),x=5-3sqrt(2)
Find the zeros of x^2-10x+7=0
The zeros of x^2-10x+7=0 are x=5+3sqrt(2),x=5-3sqrt(2)