What are the solutions to the equation x^2+12x=5 ?

The solutions to the equation x^2+12x=5 are x=-6+sqrt(41),x=-6-sqrt(41)

Find the zeros of x^2+12x=5

The zeros of x^2+12x=5 are x=-6+sqrt(41),x=-6-sqrt(41)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 12 x = 5

x = - 6 + 41, x = - 6 - 41

Solution steps

x^{2} + 12 x = 5

Move

5

to the left side

x^{2} + 12 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 5) = 241

x_{1, 2} = \frac{- 12 \pm 2 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 41}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 41}{2 \cdot 1}

x = \frac{- 12 + 2 41}{2 \cdot 1} : - 6 + 41

x = \frac{- 12 - 2 41}{2 \cdot 1} : - 6 - 41

The solutions to the quadratic equation are:

x = - 6 + 41, x = - 6 - 41

64 m^{3} n^{3}

∣ 3 x + 5 ∣ \geq - 4

5 x + 9 = 44

x^{2} + 27 = - 12 x

1 \cdot 2 = 2 \cdot 1

What are the solutions to the equation x^2+12x=5 ?
The solutions to the equation x^2+12x=5 are x=-6+sqrt(41),x=-6-sqrt(41)
Find the zeros of x^2+12x=5
The zeros of x^2+12x=5 are x=-6+sqrt(41),x=-6-sqrt(41)