What are the solutions to the equation 9r^2-3=-152 ?

The solutions to the equation 9r^2-3=-152 are r=(sqrt(149))/3 i,r=-(sqrt(149))/3 i

Find the zeros of 9r^2-3=-152

The zeros of 9r^2-3=-152 are r=(sqrt(149))/3 i,r=-(sqrt(149))/3 i

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9 r^{2} - 3 = - 152

r = \frac{149}{3} i, r = - \frac{149}{3} i

Solution steps

9 r^{2} - 3 = - 152

Move

3

to the right side

9 r^{2} = - 149

Divide both sides by

9

r^{2} = - \frac{149}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - \frac{149}{9}, r = - - \frac{149}{9}

- \frac{149}{9} = \frac{149}{3} i

- - \frac{149}{9} = - \frac{149}{3} i

r = \frac{149}{3} i, r = - \frac{149}{3} i

- \frac{\frac{4}{5}}{\frac{3}{5}}

7 x - 4 = 3 + 8 x

3 (6)^{2}

2 (7 x - 10) = 9 x - 32

2 x^{2} + 13 x + 15 = 0

What are the solutions to the equation 9r^2-3=-152 ?
The solutions to the equation 9r^2-3=-152 are r=(sqrt(149))/3 i,r=-(sqrt(149))/3 i
Find the zeros of 9r^2-3=-152
The zeros of 9r^2-3=-152 are r=(sqrt(149))/3 i,r=-(sqrt(149))/3 i