What are the solutions to the equation y^2-8y=-14 ?

The solutions to the equation y^2-8y=-14 are y=4+sqrt(2),y=4-sqrt(2)

Find the zeros of y^2-8y=-14

The zeros of y^2-8y=-14 are y=4+sqrt(2),y=4-sqrt(2)

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y^{2} - 8 y = - 14

y = 4 + 2, y = 4 - 2

Solution steps

y^{2} - 8 y = - 14

Move

14

to the left side

y^{2} - 8 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 14 = 22

y_{1, 2} = \frac{- ( - 8 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 2}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 2}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 2}{2 \cdot 1} : 4 + 2

y = \frac{- ( - 8 ) - 2 2}{2 \cdot 1} : 4 - 2

The solutions to the quadratic equation are:

y = 4 + 2, y = 4 - 2

r^{2} - 4 r - 12 = 0

4 x^{2} + 11 x + 6 = 0

3500 = x e^{0.055 \cdot 4}

6 - x \geq 2 x + 9

x^{2} = 5 x

What are the solutions to the equation y^2-8y=-14 ?
The solutions to the equation y^2-8y=-14 are y=4+sqrt(2),y=4-sqrt(2)
Find the zeros of y^2-8y=-14
The zeros of y^2-8y=-14 are y=4+sqrt(2),y=4-sqrt(2)