What are the solutions to the equation x^2-90x+1944=0 ?

The solutions to the equation x^2-90x+1944=0 are x=54,x=36

Find the zeros of x^2-90x+1944=0

The zeros of x^2-90x+1944=0 are x=54,x=36

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x^{2} - 90 x + 1944 = 0

x = 54, x = 36

Solution steps

x^{2} - 90 x + 1944 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 90 ) \pm ( - 90 ) ^{2} - 4 \cdot 1 \cdot 1944}{2 \cdot 1}

(- 90)^{2} - 4 \cdot 1 \cdot 1944 = 18

x_{1, 2} = \frac{- ( - 90 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 90 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 90 ) - 18}{2 \cdot 1}

x = \frac{- ( - 90 ) + 18}{2 \cdot 1} : 54

x = \frac{- ( - 90 ) - 18}{2 \cdot 1} : 36

The solutions to the quadratic equation are:

x = 54, x = 36

\frac{- 1}{2 11} + 11

- 2 + 3 m - 1 < 4

\frac{b ^{4}}{b ^{2}} c

- 15 x^{2} + 780 x - 1048 = 0

\frac{1}{6} (x - 15) > x + 20

What are the solutions to the equation x^2-90x+1944=0 ?
The solutions to the equation x^2-90x+1944=0 are x=54,x=36
Find the zeros of x^2-90x+1944=0
The zeros of x^2-90x+1944=0 are x=54,x=36