What are the solutions to the equation 6x^2-9x=-7x-4 ?

The solutions to the equation 6x^2-9x=-7x-4 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6

Find the zeros of 6x^2-9x=-7x-4

The zeros of 6x^2-9x=-7x-4 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6

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6 x^{2} - 9 x = - 7 x - 4

x = \frac{1}{6} + i \frac{23}{6}, x = \frac{1}{6} - i \frac{23}{6}

Solution steps

6 x^{2} - 9 x = - 7 x - 4

Move

4

to the left side

6 x^{2} - 9 x + 4 = - 7 x

Move

7 x

to the left side

6 x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

Simplify

(- 2)^{2} - 4 \cdot 6 \cdot 4 : 223 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 23 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 6}, x_{2} = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 6}

x = \frac{- ( - 2 ) + 2 23 i}{2 \cdot 6} : \frac{1}{6} + i \frac{23}{6}

x = \frac{- ( - 2 ) - 2 23 i}{2 \cdot 6} : \frac{1}{6} - i \frac{23}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{23}{6}, x = \frac{1}{6} - i \frac{23}{6}

2 + 4 Y = 0

16 x^{2} - 324

\frac{7}{30} + \frac{11}{30}

14 + 15 m + m^{2}

18 - 3 x = x 2

What are the solutions to the equation 6x^2-9x=-7x-4 ?
The solutions to the equation 6x^2-9x=-7x-4 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6
Find the zeros of 6x^2-9x=-7x-4
The zeros of 6x^2-9x=-7x-4 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6