What are the solutions to the equation -2x^2+11x=0 ?

The solutions to the equation -2x^2+11x=0 are x=0,x= 11/2

Find the zeros of -2x^2+11x=0

The zeros of -2x^2+11x=0 are x=0,x= 11/2

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- 2 x^{2} + 11 x = 0

x = 0, x = \frac{11}{2}

Decimal Notation

x = 0, x = 5.5

Solution steps

- 2 x^{2} + 11 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 1^{2} - 4 (- 2) \cdot 0 = 11

x_{1, 2} = \frac{- 11 \pm 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 11 + 11}{2 ( - 2 )}, x_{2} = \frac{- 11 - 11}{2 ( - 2 )}

x = \frac{- 11 + 11}{2 ( - 2 )} : 0

x = \frac{- 11 - 11}{2 ( - 2 )} : \frac{11}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{11}{2}

- 4 x + 5 = 0

x^{2} + 13 x y + 40 y^{2}

c^{3} + c^{7}

x^{2} + 1.2 x = 0.6 x^{2} + 1

x^{2} + 14 x y + 49 y^{2}

What are the solutions to the equation -2x^2+11x=0 ?
The solutions to the equation -2x^2+11x=0 are x=0,x= 11/2
Find the zeros of -2x^2+11x=0
The zeros of -2x^2+11x=0 are x=0,x= 11/2