What are the solutions to the equation 5x^2+9x=-4 ?

The solutions to the equation 5x^2+9x=-4 are x=-4/5 ,x=-1

Find the zeros of 5x^2+9x=-4

The zeros of 5x^2+9x=-4 are x=-4/5 ,x=-1

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5 x^{2} + 9 x = - 4

x = - \frac{4}{5}, x = - 1

Decimal Notation

x = - 0.8, x = - 1

Solution steps

5 x^{2} + 9 x = - 4

Move

4

to the left side

5 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 4 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 5}, x_{2} = \frac{- 9 - 1}{2 \cdot 5}

x = \frac{- 9 + 1}{2 \cdot 5} : - \frac{4}{5}

x = \frac{- 9 - 1}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = - \frac{4}{5}, x = - 1

x^{2} - 7 x - 30

53 \cdot \frac{π}{180}

2 x^{2} y + 2 x z^{2} + y^{2} z^{2} + x y^{3}

x^{2} + 3 x + 9 = 0

lo g_{\frac{1}{5}} (3125)

What are the solutions to the equation 5x^2+9x=-4 ?
The solutions to the equation 5x^2+9x=-4 are x=-4/5 ,x=-1
Find the zeros of 5x^2+9x=-4
The zeros of 5x^2+9x=-4 are x=-4/5 ,x=-1