What are the solutions to the equation t^2-21t=0 ?

The solutions to the equation t^2-21t=0 are t=21,t=0

Find the zeros of t^2-21t=0

The zeros of t^2-21t=0 are t=21,t=0

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t^{2} - 21 t = 0

t = 21, t = 0

Solution steps

t^{2} - 21 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 21)^{2} - 4 \cdot 1 \cdot 0 = 21

t_{1, 2} = \frac{- ( - 21 ) \pm 21}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 21 ) + 21}{2 \cdot 1}, t_{2} = \frac{- ( - 21 ) - 21}{2 \cdot 1}

t = \frac{- ( - 21 ) + 21}{2 \cdot 1} : 21

t = \frac{- ( - 21 ) - 21}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 21, t = 0

6 n^{4} + 20 n^{3} + 14 n^{2}

- 9 e^{- 0} + C = 0

\frac{\frac{2}{x} - y x}{\frac{1}{y} + \frac{1}{x ^{2}}}

\frac{2}{3}

∣ 0.5 x - 1.2 ∣ > 3.5

What are the solutions to the equation t^2-21t=0 ?
The solutions to the equation t^2-21t=0 are t=21,t=0
Find the zeros of t^2-21t=0
The zeros of t^2-21t=0 are t=21,t=0