What is (j^{-13})(j^4)(j^6) ?

The solution to (j^{-13})(j^4)(j^6) is 1/(j^3)

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simplify (j^{-13})(j^4)(j^6)

simplify

(j^{- 13}) (j^{4}) (j^{6})

\frac{1}{j ^{3}}

Solution steps

(j^{- 13}) (j^{4}) (j^{6})

Simplify

(j^{- 13}) (j^{4}) (j^{6}) : j^{- 13} j^{4} j^{6}

= j^{- 13} j^{4} j^{6}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

j^{- 13} j^{4} j^{6} = j^{- 13 + 4 + 6}

= j^{- 13 + 4 + 6}

Add/Subtract the numbers:

- 13 + 4 + 6 = - 3

= j^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

j^{- 3} = \frac{1}{j ^{3}}

= \frac{1}{j ^{3}}

9 x^{2} - 9

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3 x^{2} + 12 x + 12

(12.5) \frac{N}{m ^{2}} \cdot \frac{( 2 m ) ^{3}}{3}