What are the solutions to the equation x(x-8)=-15 ?

The solutions to the equation x(x-8)=-15 are x=5,x=3

Find the zeros of x(x-8)=-15

The zeros of x(x-8)=-15 are x=5,x=3

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x (x - 8) = - 15

x = 5, x = 3

Solution steps

x (x - 8) = - 15

Expand

x (x - 8) : x^{2} - 8 x

x^{2} - 8 x = - 15

Move

15

to the left side

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

5 \cdot 17

(- 32)^{\frac{2}{5}}

x^{2} - 4 x - 5

y^{2} + 10 y + 25

- 3 < x \leq 4

What are the solutions to the equation x(x-8)=-15 ?
The solutions to the equation x(x-8)=-15 are x=5,x=3
Find the zeros of x(x-8)=-15
The zeros of x(x-8)=-15 are x=5,x=3