What are the solutions to the equation 0=x^2-6x+3 ?

The solutions to the equation 0=x^2-6x+3 are x=3+sqrt(6),x=3-sqrt(6)

Find the zeros of 0=x^2-6x+3

The zeros of 0=x^2-6x+3 are x=3+sqrt(6),x=3-sqrt(6)

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0 = x^{2} - 6 x + 3

x = 3 + 6, x = 3 - 6

Decimal Notation

x = 5.44948 \dots, x = 0.55051 \dots

Solution steps

0 = x^{2} - 6 x + 3

Switch sides

x^{2} - 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 3 = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 6}{2 \cdot 1} : 3 + 6

x = \frac{- ( - 6 ) - 2 6}{2 \cdot 1} : 3 - 6

The solutions to the quadratic equation are:

x = 3 + 6, x = 3 - 6

25 x + 18 = 26 x + 24

\frac{d}{4} - 1 \leq 1

\frac{5 - 2 i}{5 + 3 i}

x^{2} y - 4 y + 12 - 3 x^{2}

3 x^{2} + 4 x - 7

What are the solutions to the equation 0=x^2-6x+3 ?
The solutions to the equation 0=x^2-6x+3 are x=3+sqrt(6),x=3-sqrt(6)
Find the zeros of 0=x^2-6x+3
The zeros of 0=x^2-6x+3 are x=3+sqrt(6),x=3-sqrt(6)