What are the solutions to the equation x^2-16x+62=0 ?

The solutions to the equation x^2-16x+62=0 are x=8+sqrt(2),x=8-sqrt(2)

Find the zeros of x^2-16x+62=0

The zeros of x^2-16x+62=0 are x=8+sqrt(2),x=8-sqrt(2)

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x^{2} - 16 x + 62 = 0

x = 8 + 2, x = 8 - 2

Solution steps

x^{2} - 16 x + 62 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 62}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 62 = 22

x_{1, 2} = \frac{- ( - 16 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 2}{2 \cdot 1} : 8 + 2

x = \frac{- ( - 16 ) - 2 2}{2 \cdot 1} : 8 - 2

The solutions to the quadratic equation are:

x = 8 + 2, x = 8 - 2

49 x^{2} - 64 y^{2}

b^{2} - 15 b + 56

\frac{- 100}{- 100 - 4}

x - 7 = 0

(x - 4) (x + 6) (x - 7) \geq 0

What are the solutions to the equation x^2-16x+62=0 ?
The solutions to the equation x^2-16x+62=0 are x=8+sqrt(2),x=8-sqrt(2)
Find the zeros of x^2-16x+62=0
The zeros of x^2-16x+62=0 are x=8+sqrt(2),x=8-sqrt(2)