What are the solutions to the equation 3t^2-5t-9=0 ?

The solutions to the equation 3t^2-5t-9=0 are t=(5+sqrt(133))/6 ,t=(5-sqrt(133))/6

Find the zeros of 3t^2-5t-9=0

The zeros of 3t^2-5t-9=0 are t=(5+sqrt(133))/6 ,t=(5-sqrt(133))/6

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3 t^{2} - 5 t - 9 = 0

t = \frac{5 + 133}{6}, t = \frac{5 - 133}{6}

Solution steps

3 t^{2} - 5 t - 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 9) = 133

t_{1, 2} = \frac{- ( - 5 ) \pm 133}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 133}{2 \cdot 3}, t_{2} = \frac{- ( - 5 ) - 133}{2 \cdot 3}

t = \frac{- ( - 5 ) + 133}{2 \cdot 3} : \frac{5 + 133}{6}

t = \frac{- ( - 5 ) - 133}{2 \cdot 3} : \frac{5 - 133}{6}

The solutions to the quadratic equation are:

t = \frac{5 + 133}{6}, t = \frac{5 - 133}{6}

lo g_{100} (10) = x

\frac{9}{16} = \frac{x}{12}

∣ x - 2 ∣ \geq 4

\frac{3 π}{2} + \frac{π}{4}

- 3 + 5 a = 4 a - 10

What are the solutions to the equation 3t^2-5t-9=0 ?
The solutions to the equation 3t^2-5t-9=0 are t=(5+sqrt(133))/6 ,t=(5-sqrt(133))/6
Find the zeros of 3t^2-5t-9=0
The zeros of 3t^2-5t-9=0 are t=(5+sqrt(133))/6 ,t=(5-sqrt(133))/6