What are the solutions to the equation 2x^2-8=-40 ?

The solutions to the equation 2x^2-8=-40 are x=4i,x=-4i

Find the zeros of 2x^2-8=-40

The zeros of 2x^2-8=-40 are x=4i,x=-4i

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2 x^{2} - 8 = - 40

x = 4 i, x = - 4 i

Solution steps

2 x^{2} - 8 = - 40

Move

8

to the right side

2 x^{2} = - 32

Divide both sides by

2

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

3 u \geq - 6

\frac{8 c ^{3}}{32 c ^{7}}

x^{4} - 8 x^{3} + 26 x^{2} - 32 x + 13

∣ 10 - 4 x ∣ + 1 \geq 5

y^{2} + 7 y + 6

What are the solutions to the equation 2x^2-8=-40 ?
The solutions to the equation 2x^2-8=-40 are x=4i,x=-4i
Find the zeros of 2x^2-8=-40
The zeros of 2x^2-8=-40 are x=4i,x=-4i