What is factor 27+8y^3 ?

The solution to factor 27+8y^3 is (2y+3)(4y^2-6y+9)

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factor 27+8y^3

factor

27 + 8 y^{3}

(2 y + 3) (4 y^{2} - 6 y + 9)

Solution steps

27 + 8 y^{3}

Write in the standard form

= 8 y^{3} + 27

Apply exponent rules

= (2 y)^{3} + 3^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 y)^{3} + 3^{3} = (2 y + 3) (2^{2} y^{2} - 3 \cdot 2 y + 3^{2})

= (2 y + 3) (2^{2} y^{2} - 3 \cdot 2 y + 3^{2})

Simplify

(2 y + 3) (2^{2} y^{2} - 3 \cdot 2 y + 3^{2}) : (2 y + 3) (4 y^{2} - 6 y + 9)

= (2 y + 3) (4 y^{2} - 6 y + 9)

x^{2} - 100 x + 1275

(2 - 2)^{3}

(\frac{2 m}{3 n})^{- 3}

- 2 x + 6 < x - 6

2 x^{3} - x^{2} - 25 x - 12