What is the answer to (x+1)(2x+3)=2x^2+8x+5 ?

The answer to (x+1)(2x+3)=2x^2+8x+5 is x=-2/3

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(x+1)(2x+3)=2x^2+8x+5

(x + 1) (2 x + 3) = 2 x^{2} + 8 x + 5

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

(x + 1) (2 x + 3) = 2 x^{2} + 8 x + 5

Expand

(x + 1) (2 x + 3) : 2 x^{2} + 5 x + 3

2 x^{2} + 5 x + 3 = 2 x^{2} + 8 x + 5

Move

3

to the right side

2 x^{2} + 5 x = 2 x^{2} + 8 x + 2

Subtract

2 x^{2} + 8 x

from both sides

2 x^{2} + 5 x - (2 x^{2} + 8 x) = 2 x^{2} + 8 x + 2 - (2 x^{2} + 8 x)

Simplify

- 3 x = 2

Divide both sides by

- 3

x = - \frac{2}{3}

y^{2} - 9 y + 14

81 x^{4} - 1

b^{4} - b^{3}

\frac{1}{2} (- 2) - 4

\frac{a}{4} = 18

What is the answer to (x+1)(2x+3)=2x^2+8x+5 ?
The answer to (x+1)(2x+3)=2x^2+8x+5 is x=-2/3
Solve for x: (x+1)(2x+3)=2x^2+8x+5
The solution is x=-2/3