What is factor 6x^3-5x^2-12x-4 ?

The solution to factor 6x^3-5x^2-12x-4 is (2x+1)(3x+2)(x-2)

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factor 6x^3-5x^2-12x-4

factor

6 x^{3} - 5 x^{2} - 12 x - 4

(2 x + 1) (3 x + 2) (x - 2)

Solution steps

6 x^{3} - 5 x^{2} - 12 x - 4

Use the rational root theorem

= (2 x + 1) \frac{6 x ^{3} - 5 x ^{2} - 12 x - 4}{2 x + 1}

\frac{6 x ^{3} - 5 x ^{2} - 12 x - 4}{2 x + 1} = 3 x^{2} - 4 x - 4

= (2 x + 1) (3 x^{2} - 4 x - 4)

Factor

3 x^{2} - 4 x - 4 : (3 x + 2) (x - 2)

= (2 x + 1) (3 x + 2) (x - 2)

4 a^{2} - 9 c^{2}

- 2 x + 5 > 11

(2 r)^{\frac{7}{4}}

(64 x^{15} y^{- 3})^{\frac{1}{3}}

\frac{x}{2 - x} > 2

What is factor 6x^3-5x^2-12x-4 ?
The solution to factor 6x^3-5x^2-12x-4 is (2x+1)(3x+2)(x-2)