What are the solutions to the equation 8x^2-10x-26=-10 ?

The solutions to the equation 8x^2-10x-26=-10 are x=(5+3sqrt(17))/8 ,x=(5-3sqrt(17))/8

Find the zeros of 8x^2-10x-26=-10

The zeros of 8x^2-10x-26=-10 are x=(5+3sqrt(17))/8 ,x=(5-3sqrt(17))/8

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8 x^{2} - 10 x - 26 = - 10

x = \frac{5 + 3 17}{8}, x = \frac{5 - 3 17}{8}

Solution steps

8 x^{2} - 10 x - 26 = - 10

Move

10

to the left side

8 x^{2} - 10 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 8 ( - 16 )}{2 \cdot 8}

(- 10)^{2} - 4 \cdot 8 (- 16) = 617

x_{1, 2} = \frac{- ( - 10 ) \pm 6 17}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6 17}{2 \cdot 8}, x_{2} = \frac{- ( - 10 ) - 6 17}{2 \cdot 8}

x = \frac{- ( - 10 ) + 6 17}{2 \cdot 8} : \frac{5 + 3 17}{8}

x = \frac{- ( - 10 ) - 6 17}{2 \cdot 8} : \frac{5 - 3 17}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 3 17}{8}, x = \frac{5 - 3 17}{8}

- \frac{3}{8} + \frac{1}{2}

49 x^{2} - 4

z^{2} + 3 z - 4 = 0

2 x + 2 = x^{2} + x - 4

b - 2 = 3

What are the solutions to the equation 8x^2-10x-26=-10 ?
The solutions to the equation 8x^2-10x-26=-10 are x=(5+3sqrt(17))/8 ,x=(5-3sqrt(17))/8
Find the zeros of 8x^2-10x-26=-10
The zeros of 8x^2-10x-26=-10 are x=(5+3sqrt(17))/8 ,x=(5-3sqrt(17))/8