What are the solutions to the equation (t+3)^2=5 ?

The solutions to the equation (t+3)^2=5 are t=sqrt(5)-3,t=-sqrt(5)-3

Find the zeros of (t+3)^2=5

The zeros of (t+3)^2=5 are t=sqrt(5)-3,t=-sqrt(5)-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(t + 3)^{2} = 5

t = 5 - 3, t = - 5 - 3

Decimal Notation

t = - 0.76393 \dots, t = - 5.23606 \dots

Solution steps

(t + 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t + 3 = 5 : t = 5 - 3

Solve

t + 3 = - 5 : t = - 5 - 3

The solutions to the quadratic equation are:

t = 5 - 3, t = - 5 - 3

x^{2} - 2 x - 3 = 4

(6 k^{4}) (- k^{2})

\frac{19 - 4 i}{2 - 5 i} + \frac{3 + 2 i}{i}

6 x^{2} - 55 x + 9

25 a^{2} - 20 a + 4

What are the solutions to the equation (t+3)^2=5 ?
The solutions to the equation (t+3)^2=5 are t=sqrt(5)-3,t=-sqrt(5)-3
Find the zeros of (t+3)^2=5
The zeros of (t+3)^2=5 are t=sqrt(5)-3,t=-sqrt(5)-3