What are the solutions to the equation x^2+14x+17=-96 ?

The solutions to the equation x^2+14x+17=-96 are x=-7+8i,x=-7-8i

Find the zeros of x^2+14x+17=-96

The zeros of x^2+14x+17=-96 are x=-7+8i,x=-7-8i

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x^{2} + 14 x + 17 = - 96

x = - 7 + 8 i, x = - 7 - 8 i

Solution steps

x^{2} + 14 x + 17 = - 96

Move

96

to the left side

x^{2} + 14 x + 113 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 113}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot 113 : 16 i

x_{1, 2} = \frac{- 14 \pm 16 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 16 i}{2 \cdot 1}, x_{2} = \frac{- 14 - 16 i}{2 \cdot 1}

x = \frac{- 14 + 16 i}{2 \cdot 1} : - 7 + 8 i

x = \frac{- 14 - 16 i}{2 \cdot 1} : - 7 - 8 i

The solutions to the quadratic equation are:

x = - 7 + 8 i, x = - 7 - 8 i

\frac{5 π}{12} - \frac{π}{4}

8 x + 9 \leq 16 x - 13

6 + 5 x = 9 x - 4 + 6 x

8 x^{2} - 8

What are the solutions to the equation x^2+14x+17=-96 ?
The solutions to the equation x^2+14x+17=-96 are x=-7+8i,x=-7-8i
Find the zeros of x^2+14x+17=-96
The zeros of x^2+14x+17=-96 are x=-7+8i,x=-7-8i