What are the solutions to the equation 2x^2-4x-2=0 ?

The solutions to the equation 2x^2-4x-2=0 are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of 2x^2-4x-2=0

The zeros of 2x^2-4x-2=0 are x=1+sqrt(2),x=1-sqrt(2)

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2 x^{2} - 4 x - 2 = 0

x = 1 + 2, x = 1 - 2

Solution steps

2 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 2) = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 2}{2 \cdot 2} : 1 + 2

x = \frac{- ( - 4 ) - 4 2}{2 \cdot 2} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

60 x^{2} - 50 x - 60 = 0

\frac{π}{2} \cdot \frac{1}{2}

16 x - 5 = 1 + 13 x

2 (x + 6) = 7 x + 5

e^{x} < 10

What are the solutions to the equation 2x^2-4x-2=0 ?
The solutions to the equation 2x^2-4x-2=0 are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of 2x^2-4x-2=0
The zeros of 2x^2-4x-2=0 are x=1+sqrt(2),x=1-sqrt(2)