What are the solutions to the equation r^2-3r-54=0 ?

The solutions to the equation r^2-3r-54=0 are r=9,r=-6

Find the zeros of r^2-3r-54=0

The zeros of r^2-3r-54=0 are r=9,r=-6

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r^{2} - 3 r - 54 = 0

r = 9, r = - 6

Solution steps

r^{2} - 3 r - 54 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 54) = 15

r_{1, 2} = \frac{- ( - 3 ) \pm 15}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 3 ) + 15}{2 \cdot 1}, r_{2} = \frac{- ( - 3 ) - 15}{2 \cdot 1}

r = \frac{- ( - 3 ) + 15}{2 \cdot 1} : 9

r = \frac{- ( - 3 ) - 15}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

r = 9, r = - 6

2 k^{2} + 7 k + 6

(x + 6)^{2} = - 25

(5^{\frac{1}{2}})^{2}

- 9 = q - 4.8

∣ 3 x - 2 ∣ < 10

What are the solutions to the equation r^2-3r-54=0 ?
The solutions to the equation r^2-3r-54=0 are r=9,r=-6
Find the zeros of r^2-3r-54=0
The zeros of r^2-3r-54=0 are r=9,r=-6