What are the solutions to the equation x^2-2x+2/3 =0 ?

The solutions to the equation x^2-2x+2/3 =0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

Find the zeros of x^2-2x+2/3 =0

The zeros of x^2-2x+2/3 =0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

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x^{2} - 2 x + \frac{2}{3} = 0

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

Decimal Notation

x = 1.57735 \dots, x = 0.42264 \dots

Solution steps

x^{2} - 2 x + \frac{2}{3} = 0

Multiply both sides by

3

3 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 2 = 23

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 3}{2 \cdot 3} : \frac{3 + 3}{3}

x = \frac{- ( - 6 ) - 2 3}{2 \cdot 3} : \frac{3 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

x^{2} = 11

3 x^{- 4}

6 (2 x - 1) - 12 = - 2 (x + 10)

1 = ∣ x ∣ - 1

\frac{12}{x - 2} < 6

What are the solutions to the equation x^2-2x+2/3 =0 ?
The solutions to the equation x^2-2x+2/3 =0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3
Find the zeros of x^2-2x+2/3 =0
The zeros of x^2-2x+2/3 =0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3