What is (2x+3)/6 >= (5x-7)/2 ?

The solution to (2x+3)/6 >= (5x-7)/2 is x<= 24/13

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(2x+3)/6 >= (5x-7)/2

\frac{2 x + 3}{6} \geq \frac{5 x - 7}{2}

x \leq \frac{24}{13}

Interval Notation

(- \infty, \frac{24}{13}]

Decimal Notation

x \leq 1.84615 \dots

Solution steps

\frac{2 x + 3}{6} \geq \frac{5 x - 7}{2}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 x + 3) \cdot 2 \geq 6 (5 x - 7)

Expand

(2 x + 3) \cdot 2 : 4 x + 6

Expand

6 (5 x - 7) : 30 x - 42

4 x + 6 \geq 30 x - 42

Move

6

to the right side

4 x \geq 30 x - 48

Move

30 x

to the left side

- 26 x \geq - 48

Multiply both sides by

- 1

26 x \leq 48

Divide both sides by

26

x \leq \frac{24}{13}

ln (250) = 5.521

p^{4} (m - 2 n) + q (m - 2 n)

x + 2 = - 1

2 v^{2} - 13 v + 2 = (v - 4)^{2}

(1 \frac{1}{3})^{3}

What is (2x+3)/6 >= (5x-7)/2 ?
The solution to (2x+3)/6 >= (5x-7)/2 is x<= 24/13