What are the solutions to the equation 1/5 t^2-36=0 ?

The solutions to the equation 1/5 t^2-36=0 are t=6sqrt(5),t=-6sqrt(5)

Find the zeros of 1/5 t^2-36=0

The zeros of 1/5 t^2-36=0 are t=6sqrt(5),t=-6sqrt(5)

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\frac{1}{5} t^{2} - 36 = 0

t = 65, t = - 65

Solution steps

\frac{1}{5} t^{2} - 36 = 0

Move

36

to the right side

\frac{1}{5} t^{2} = 36

Multiply both sides by

5

t^{2} = 180

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 180, t = - 180

180 = 65

- 180 = - 65

t = 65, t = - 65

lo g_{4} (192) - lo g_{4} (3)

(5 x - 1)^{2} = 1

2 x^{2} - 3 x - 4 = 0

3 x^{3} - 5 x^{2} - 2 x

m^{2} = 17

What are the solutions to the equation 1/5 t^2-36=0 ?
The solutions to the equation 1/5 t^2-36=0 are t=6sqrt(5),t=-6sqrt(5)
Find the zeros of 1/5 t^2-36=0
The zeros of 1/5 t^2-36=0 are t=6sqrt(5),t=-6sqrt(5)