What are the solutions to the equation 9x^2-3x+2=0 ?

The solutions to the equation 9x^2-3x+2=0 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6

Find the zeros of 9x^2-3x+2=0

The zeros of 9x^2-3x+2=0 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6

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9 x^{2} - 3 x + 2 = 0

x = \frac{1}{6} + i \frac{7}{6}, x = \frac{1}{6} - i \frac{7}{6}

Solution steps

9 x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

(- 3)^{2} - 4 \cdot 9 \cdot 2 : 37 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 7 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 7 i}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 3 7 i}{2 \cdot 9}

x = \frac{- ( - 3 ) + 3 7 i}{2 \cdot 9} : \frac{1}{6} + i \frac{7}{6}

x = \frac{- ( - 3 ) - 3 7 i}{2 \cdot 9} : \frac{1}{6} - i \frac{7}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{7}{6}, x = \frac{1}{6} - i \frac{7}{6}

- 5 x \leq 30

\frac{2 x - 5}{x ^{2} - 6 x - 7} < \frac{1}{x - 3}

\frac{1}{2 9}

4 x^{2} y - 16 y

5 x + 8 = - 8 + 3 x

What are the solutions to the equation 9x^2-3x+2=0 ?
The solutions to the equation 9x^2-3x+2=0 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6
Find the zeros of 9x^2-3x+2=0
The zeros of 9x^2-3x+2=0 are x= 1/6+i(sqrt(7))/6 ,x= 1/6-i(sqrt(7))/6