What are the solutions to the equation 5(x^2-10)+5=-10 ?

The solutions to the equation 5(x^2-10)+5=-10 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 5(x^2-10)+5=-10

The zeros of 5(x^2-10)+5=-10 are x=sqrt(7),x=-sqrt(7)

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5 (x^{2} - 10) + 5 = - 10

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

5 (x^{2} - 10) + 5 = - 10

Move

5

to the right side

5 (x^{2} - 10) = - 15

Divide both sides by

5

x^{2} - 10 = - 3

Move

10

to the right side

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

c + 5 = 5

x^{2} + 25 x = 0

\frac{x + 4}{6} + \frac{3 - 5 x}{5} = \frac{x - 1}{4}

a = π (4)^{2}

lo g_{6} (8)

What are the solutions to the equation 5(x^2-10)+5=-10 ?
The solutions to the equation 5(x^2-10)+5=-10 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 5(x^2-10)+5=-10
The zeros of 5(x^2-10)+5=-10 are x=sqrt(7),x=-sqrt(7)