What are the solutions to the equation 9x^2-43x-10=0 ?

The solutions to the equation 9x^2-43x-10=0 are x=5,x=-2/9

Find the zeros of 9x^2-43x-10=0

The zeros of 9x^2-43x-10=0 are x=5,x=-2/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 43 x - 10 = 0

x = 5, x = - \frac{2}{9}

Decimal Notation

x = 5, x = - 0.22222 \dots

Solution steps

9 x^{2} - 43 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 43 ) \pm ( - 43 ) ^{2} - 4 \cdot 9 ( - 10 )}{2 \cdot 9}

(- 43)^{2} - 4 \cdot 9 (- 10) = 47

x_{1, 2} = \frac{- ( - 43 ) \pm 47}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 43 ) + 47}{2 \cdot 9}, x_{2} = \frac{- ( - 43 ) - 47}{2 \cdot 9}

x = \frac{- ( - 43 ) + 47}{2 \cdot 9} : 5

x = \frac{- ( - 43 ) - 47}{2 \cdot 9} : - \frac{2}{9}

The solutions to the quadratic equation are:

x = 5, x = - \frac{2}{9}

\frac{x + 3}{x - 5} < 1

8 y^{2} + 56 y + 96

3 (8 - 2 x) = - 6 (x + 4)

3 x + 6 = 4 x

- 4 x^{2} - 83 x = - 3 x + 396

What are the solutions to the equation 9x^2-43x-10=0 ?
The solutions to the equation 9x^2-43x-10=0 are x=5,x=-2/9
Find the zeros of 9x^2-43x-10=0
The zeros of 9x^2-43x-10=0 are x=5,x=-2/9