What are the solutions to the equation 5x^2+6x-1=0 ?

The solutions to the equation 5x^2+6x-1=0 are x=(-3+sqrt(14))/5 ,x=-(3+sqrt(14))/5

Find the zeros of 5x^2+6x-1=0

The zeros of 5x^2+6x-1=0 are x=(-3+sqrt(14))/5 ,x=-(3+sqrt(14))/5

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5 x^{2} + 6 x - 1 = 0

x = \frac{- 3 + 14}{5}, x = - \frac{3 + 14}{5}

Decimal Notation

x = 0.14833 \dots, x = - 1.34833 \dots

Solution steps

5 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 1) = 214

x_{1, 2} = \frac{- 6 \pm 2 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 2 14}{2 \cdot 5}, x_{2} = \frac{- 6 - 2 14}{2 \cdot 5}

x = \frac{- 6 + 2 14}{2 \cdot 5} : \frac{- 3 + 14}{5}

x = \frac{- 6 - 2 14}{2 \cdot 5} : - \frac{3 + 14}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 14}{5}, x = - \frac{3 + 14}{5}

(0.5 n^{5})^{2} (10 n^{7})^{3}

4 + ∣ 2 x - 7 ∣ = 14

a + 8 = 9 \cdot 3 - 10

\frac{8}{9} \cdot \frac{4}{7}

75 x^{3} - 27 x

What are the solutions to the equation 5x^2+6x-1=0 ?
The solutions to the equation 5x^2+6x-1=0 are x=(-3+sqrt(14))/5 ,x=-(3+sqrt(14))/5
Find the zeros of 5x^2+6x-1=0
The zeros of 5x^2+6x-1=0 are x=(-3+sqrt(14))/5 ,x=-(3+sqrt(14))/5