What are the solutions to the equation 0=x^2-4x+6 ?

The solutions to the equation 0=x^2-4x+6 are x=2+sqrt(2)i,x=2-sqrt(2)i

Find the zeros of 0=x^2-4x+6

The zeros of 0=x^2-4x+6 are x=2+sqrt(2)i,x=2-sqrt(2)i

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0 = x^{2} - 4 x + 6

x = 2 + 2 i, x = 2 - 2 i

Solution steps

0 = x^{2} - 4 x + 6

Switch sides

x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 6 : 22 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 2 i}{2 \cdot 1} : 2 + 2 i

x = \frac{- ( - 4 ) - 2 2 i}{2 \cdot 1} : 2 - 2 i

The solutions to the quadratic equation are:

x = 2 + 2 i, x = 2 - 2 i

43 x = 7^{8} - 7^{7} + 7^{6}

3 x^{2} + 160 = 80

(1 + 3)^{2}

(2^{2})^{\frac{1}{2}}

3 (x - 7) > 18

What are the solutions to the equation 0=x^2-4x+6 ?
The solutions to the equation 0=x^2-4x+6 are x=2+sqrt(2)i,x=2-sqrt(2)i
Find the zeros of 0=x^2-4x+6
The zeros of 0=x^2-4x+6 are x=2+sqrt(2)i,x=2-sqrt(2)i