What are the solutions to the equation 2x^2+11x+14=0 ?

The solutions to the equation 2x^2+11x+14=0 are x=-2,x=-7/2

Find the zeros of 2x^2+11x+14=0

The zeros of 2x^2+11x+14=0 are x=-2,x=-7/2

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2 x^{2} + 11 x + 14 = 0

x = - 2, x = - \frac{7}{2}

Decimal Notation

x = - 2, x = - 3.5

Solution steps

2 x^{2} + 11 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 14 = 3

x_{1, 2} = \frac{- 11 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 3}{2 \cdot 2}, x_{2} = \frac{- 11 - 3}{2 \cdot 2}

x = \frac{- 11 + 3}{2 \cdot 2} : - 2

x = \frac{- 11 - 3}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - 2, x = - \frac{7}{2}

16 - 8

\frac{x}{8} = \frac{10}{4}

11 - 2 x^{2} = 5

5 (6) + 7 (0) = - 3

- \frac{1}{3} \leq \frac{x + 1}{6} < \frac{4}{3}

What are the solutions to the equation 2x^2+11x+14=0 ?
The solutions to the equation 2x^2+11x+14=0 are x=-2,x=-7/2
Find the zeros of 2x^2+11x+14=0
The zeros of 2x^2+11x+14=0 are x=-2,x=-7/2