What are the solutions to the equation x^2+2x=80 ?

The solutions to the equation x^2+2x=80 are x=8,x=-10

Find the zeros of x^2+2x=80

The zeros of x^2+2x=80 are x=8,x=-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x = 80

x = 8, x = - 10

Solution steps

x^{2} + 2 x = 80

Move

80

to the left side

x^{2} + 2 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 80) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 18}{2 \cdot 1}, x_{2} = \frac{- 2 - 18}{2 \cdot 1}

x = \frac{- 2 + 18}{2 \cdot 1} : 8

x = \frac{- 2 - 18}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 8, x = - 10

1 5^{2} + 1 2^{2}

\frac{( x ^{2} y ) ^{- 3}}{( x y ) ^{2}}

2 ∣ 3 x - 2 ∣ = 14

81 x^{2} - 4 v^{2}

4 y^{2} - x^{2}

What are the solutions to the equation x^2+2x=80 ?
The solutions to the equation x^2+2x=80 are x=8,x=-10
Find the zeros of x^2+2x=80
The zeros of x^2+2x=80 are x=8,x=-10