What is (8(-m^0n^2)^3(-n^3)^2)/(m^6n^0(-2m^{-2)n^4)^3} ?

The solution to (8(-m^0n^2)^3(-n^3)^2)/(m^6n^0(-2m^{-2)n^4)^3} is 1

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simplify (8(-m^0n^2)^3(-n^3)^2)/(m^6n^0(-2m^{-2)n^4)^3}

simplify

\frac{8 ( - m ^{0} n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{m ^{6} n ^{0} ( - 2 m ^{- 2} n ^{4} ) ^{3}}

1

Solution steps

\frac{8 ( - m ^{0} n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{m ^{6} n ^{0} ( - 2 m ^{- 2} n ^{4} ) ^{3}}

Simplify

\frac{8 ( - m ^{0} n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{m ^{6} n ^{0} ( - 2 m ^{- 2} n ^{4} ) ^{3}} : \frac{8 ( - n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{m ^{6} ( - 2 m ^{- 2} n ^{4} ) ^{3}}

= \frac{8 ( - n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{m ^{6} ( - 2 m ^{- 2} n ^{4} ) ^{3}}

m^{6} (- 2 m^{- 2} n^{4})^{3} = - m^{6} (2 m^{- 2} n^{4})^{3}

= \frac{8 ( - n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{- m ^{6} ( 2 m ^{- 2} n ^{4} ) ^{3}}

Simplify

(2 m^{- 2} n^{4})^{3} : 2^{3} \cdot \frac{1}{m ^{6}} n^{12}

= \frac{8 ( - n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{- m ^{6} \cdot 2 ^{3} \cdot \frac{1}{m ^{6}} n ^{12}}

Factor the number:

8 = 2^{3}

= \frac{2 ^{3} ( - n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{- m ^{6} \cdot 2 ^{3} \cdot \frac{1}{m ^{6}} n ^{12}}

Cancel the common factor:

2^{3}

= \frac{( - n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{- m ^{6} \frac{1}{m ^{6}} n ^{12}}

Simplify

\frac{( - n ^{2} ) ^{3} ( - n ^{3} ) ^{2}}{- m ^{6} \frac{1}{m ^{6}} n ^{12}} : 1

= 1

x^{3} + 4 x^{2} < 4 x + 16

\frac{x}{2} - 3 = 4

\frac{x}{6} = - 4

(4^{3})^{2}

π - \frac{3 π}{4}

What is (8(-m^0n^2)^3(-n^3)^2)/(m^6n^0(-2m^{-2)n^4)^3} ?
The solution to (8(-m^0n^2)^3(-n^3)^2)/(m^6n^0(-2m^{-2)n^4)^3} is 1