What are the solutions to the equation x^2-2x=12 ?

The solutions to the equation x^2-2x=12 are x=1+sqrt(13),x=1-sqrt(13)

Find the zeros of x^2-2x=12

The zeros of x^2-2x=12 are x=1+sqrt(13),x=1-sqrt(13)

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x^{2} - 2 x = 12

x = 1 + 13, x = 1 - 13

Decimal Notation

x = 4.60555 \dots, x = - 2.60555 \dots

Solution steps

x^{2} - 2 x = 12

Move

12

to the left side

x^{2} - 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 12) = 213

x_{1, 2} = \frac{- ( - 2 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 13}{2 \cdot 1} : 1 + 13

x = \frac{- ( - 2 ) - 2 13}{2 \cdot 1} : 1 - 13

The solutions to the quadratic equation are:

x = 1 + 13, x = 1 - 13

- \frac{1.2 ( 5 )}{( 0.01 ( 5 ) ^{2} + 1 ) ^{2}}

2 (3 z - 1) = 46

5 a^{4} - 245

0 = x + 3

5 y^{4} + 13 y^{3} - 6 y^{2}

What are the solutions to the equation x^2-2x=12 ?
The solutions to the equation x^2-2x=12 are x=1+sqrt(13),x=1-sqrt(13)
Find the zeros of x^2-2x=12
The zeros of x^2-2x=12 are x=1+sqrt(13),x=1-sqrt(13)