What are the solutions to the equation 2x(x-1)=7x^2-3x ?

The solutions to the equation 2x(x-1)=7x^2-3x are x=0,x= 1/5

Find the zeros of 2x(x-1)=7x^2-3x

The zeros of 2x(x-1)=7x^2-3x are x=0,x= 1/5

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2 x (x - 1) = 7 x^{2} - 3 x

x = 0, x = \frac{1}{5}

Decimal Notation

x = 0, x = 0.2

Solution steps

2 x (x - 1) = 7 x^{2} - 3 x

Expand

2 x (x - 1) : 2 x^{2} - 2 x

2 x^{2} - 2 x = 7 x^{2} - 3 x

Move

3 x

to the left side

2 x^{2} + x = 7 x^{2}

Move

7 x^{2}

to the left side

- 5 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

1^{2} - 4 (- 5) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 5 )}, x_{2} = \frac{- 1 - 1}{2 ( - 5 )}

x = \frac{- 1 + 1}{2 ( - 5 )} : 0

x = \frac{- 1 - 1}{2 ( - 5 )} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{5}

7 5^{2}

- 3 + 9 \geq - 21

x^{2} - (x + 1) 2 = 2 - x^{2}

0 = - 5 n - 2 n

\frac{- 2}{3} - 1

What are the solutions to the equation 2x(x-1)=7x^2-3x ?
The solutions to the equation 2x(x-1)=7x^2-3x are x=0,x= 1/5
Find the zeros of 2x(x-1)=7x^2-3x
The zeros of 2x(x-1)=7x^2-3x are x=0,x= 1/5