What is the answer to (3x-2)(x+4)-3(x+5)(x-1)=0 ?

The answer to (3x-2)(x+4)-3(x+5)(x-1)=0 is x= 7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3x-2)(x+4)-3(x+5)(x-1)=0

(3 x - 2) (x + 4) - 3 (x + 5) (x - 1) = 0

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

(3 x - 2) (x + 4) - 3 (x + 5) (x - 1) = 0

Expand

(3 x - 2) (x + 4) - 3 (x + 5) (x - 1) : - 2 x + 7

- 2 x + 7 = 0

Move

7

to the right side

- 2 x = - 7

Divide both sides by

- 2

x = \frac{7}{2}

2 x - 14 = 7 x + 6

\frac{2 π}{45} \cdot 6400

(x^{2} - 1)^{\frac{3}{2}}

\frac{y}{x} + \frac{x}{y}

8 (x - 3) > 4 (2 x - 6)

What is the answer to (3x-2)(x+4)-3(x+5)(x-1)=0 ?
The answer to (3x-2)(x+4)-3(x+5)(x-1)=0 is x= 7/2
Solve for x: (3x-2)(x+4)-3(x+5)(x-1)=0
The solution is x= 7/2