What is (8x)/(x^2-36)>= 0 ?

The solution to (8x)/(x^2-36)>= 0 is -6 6

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(8x)/(x^2-36)>= 0

\frac{8 x}{x ^{2} - 36} \geq 0

- 6 < x \leq 0 or x > 6

Interval Notation

(- 6, 0] \cup (6, \infty)

Solution steps

\frac{8 x}{x ^{2} - 36} \geq 0

Rewrite in standard form

\frac{x}{x ^{2} - 36} \geq 0

Factor

\frac{x}{x ^{2} - 36} : \frac{x}{( x + 6 ) ( x - 6 )}

\frac{x}{( x + 6 ) ( x - 6 )} \geq 0

Identify the intervals

- 6 < x \leq 0 or x > 6

a^{2} + 5 a + 6

∣ - 1 - 6 x ∣ < 7

46 \cdot 21

3 \cdot 16

\frac{5}{2} + \frac{5}{4}

What is (8x)/(x^2-36)>= 0 ?
The solution to (8x)/(x^2-36)>= 0 is -6<x<= 0\lor x>6