What are the solutions to the equation 2x^2-96x=0 ?

The solutions to the equation 2x^2-96x=0 are x=48,x=0

Find the zeros of 2x^2-96x=0

The zeros of 2x^2-96x=0 are x=48,x=0

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2 x^{2} - 96 x = 0

x = 48, x = 0

Solution steps

2 x^{2} - 96 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 96)^{2} - 4 \cdot 2 \cdot 0 = 96

x_{1, 2} = \frac{- ( - 96 ) \pm 96}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 96}{2 \cdot 2}, x_{2} = \frac{- ( - 96 ) - 96}{2 \cdot 2}

x = \frac{- ( - 96 ) + 96}{2 \cdot 2} : 48

x = \frac{- ( - 96 ) - 96}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 48, x = 0

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What are the solutions to the equation 2x^2-96x=0 ?
The solutions to the equation 2x^2-96x=0 are x=48,x=0
Find the zeros of 2x^2-96x=0
The zeros of 2x^2-96x=0 are x=48,x=0