What are the solutions to the equation 3x^2-26x+11=-5 ?

The solutions to the equation 3x^2-26x+11=-5 are x=8,x= 2/3

Find the zeros of 3x^2-26x+11=-5

The zeros of 3x^2-26x+11=-5 are x=8,x= 2/3

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3 x^{2} - 26 x + 11 = - 5

x = 8, x = \frac{2}{3}

Solution steps

3 x^{2} - 26 x + 11 = - 5

Move

5

to the left side

3 x^{2} - 26 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

(- 26)^{2} - 4 \cdot 3 \cdot 16 = 22

x_{1, 2} = \frac{- ( - 26 ) \pm 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 22}{2 \cdot 3}, x_{2} = \frac{- ( - 26 ) - 22}{2 \cdot 3}

x = \frac{- ( - 26 ) + 22}{2 \cdot 3} : 8

x = \frac{- ( - 26 ) - 22}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 8, x = \frac{2}{3}

\frac{- 4 y ^{- 2}}{8 x ^{- 2}}

\frac{1}{2} + \frac{3}{4}

\frac{35 x ^{3} y ^{8}}{14 x ^{2} y ^{3}}

x + 6 = - 7

3 (x - 2) = 18

What are the solutions to the equation 3x^2-26x+11=-5 ?
The solutions to the equation 3x^2-26x+11=-5 are x=8,x= 2/3
Find the zeros of 3x^2-26x+11=-5
The zeros of 3x^2-26x+11=-5 are x=8,x= 2/3