What are the solutions to the equation 0.0115=P^2 ?

The solutions to the equation 0.0115=P^2 are P=(sqrt(23))/(20sqrt(5)),P=-(sqrt(23))/(20sqrt(5))

Find the zeros of 0.0115=P^2

The zeros of 0.0115=P^2 are P=(sqrt(23))/(20sqrt(5)),P=-(sqrt(23))/(20sqrt(5))

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0.0115 = P^{2}

P = \frac{23}{20 5}, P = - \frac{23}{20 5}

Decimal Notation

P = 0.10723 \dots, P = - 0.10723 \dots

Solution steps

0.0115 = P^{2}

Switch sides

P^{2} = 0.0115

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

P = 0.0115, P = - 0.0115

0.0115 = \frac{23}{20 5}

- 0.0115 = - \frac{23}{20 5}

P = \frac{23}{20 5}, P = - \frac{23}{20 5}

12 + 5 x = 2 x + 18

x^{2} + 21 x + 54

\frac{3}{x - 2} > 7

\frac{x + 5}{x - 6} < 0

x^{3} + x^{2} \geq 12 x

What are the solutions to the equation 0.0115=P^2 ?
The solutions to the equation 0.0115=P^2 are P=(sqrt(23))/(20sqrt(5)),P=-(sqrt(23))/(20sqrt(5))
Find the zeros of 0.0115=P^2
The zeros of 0.0115=P^2 are P=(sqrt(23))/(20sqrt(5)),P=-(sqrt(23))/(20sqrt(5))