What are the solutions to the equation (x-2)(x+9)=0 ?

The solutions to the equation (x-2)(x+9)=0 are x=2,x=-9

Find the zeros of (x-2)(x+9)=0

The zeros of (x-2)(x+9)=0 are x=2,x=-9

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(x - 2) (x + 9) = 0

x = 2, x = - 9

Solution steps

(x - 2) (x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 9 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 9 = 0 : x = - 9

The solutions to the quadratic equation are:

x = 2, x = - 9

2 x + (7 x + 9) = 90

x^{2} = 147

(81 x^{- 12} y^{32})^{\frac{3}{4}}

\frac{1}{i ^{2}}

4 x + 9 \geq - 11

What are the solutions to the equation (x-2)(x+9)=0 ?
The solutions to the equation (x-2)(x+9)=0 are x=2,x=-9
Find the zeros of (x-2)(x+9)=0
The zeros of (x-2)(x+9)=0 are x=2,x=-9