What are the solutions to the equation 2z^2=13z+15 ?

The solutions to the equation 2z^2=13z+15 are z= 15/2 ,z=-1

Find the zeros of 2z^2=13z+15

The zeros of 2z^2=13z+15 are z= 15/2 ,z=-1

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2 z^{2} = 13 z + 15

z = \frac{15}{2}, z = - 1

Decimal Notation

z = 7.5, z = - 1

Solution steps

2 z^{2} = 13 z + 15

Move

15

to the left side

2 z^{2} - 15 = 13 z

Move

13 z

to the left side

2 z^{2} - 15 - 13 z = 0

Write in the standard form

a x^{2} + b x + c = 0

2 z^{2} - 13 z - 15 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 (- 15) = 17

z_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 2}, z_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 2}

z = \frac{- ( - 13 ) + 17}{2 \cdot 2} : \frac{15}{2}

z = \frac{- ( - 13 ) - 17}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

z = \frac{15}{2}, z = - 1

\frac{5 a ^{7}}{10 a ^{3}}

12 (p^{2} - 1) = 7 p

6^{- 7}

\frac{- 10}{5}

x + 5 = 2 x - 7

What are the solutions to the equation 2z^2=13z+15 ?
The solutions to the equation 2z^2=13z+15 are z= 15/2 ,z=-1
Find the zeros of 2z^2=13z+15
The zeros of 2z^2=13z+15 are z= 15/2 ,z=-1