What are the solutions to the equation 90=w^2+5w+6 ?

The solutions to the equation 90=w^2+5w+6 are w=7,w=-12

Find the zeros of 90=w^2+5w+6

The zeros of 90=w^2+5w+6 are w=7,w=-12

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90 = w^{2} + 5 w + 6

w = 7, w = - 12

Solution steps

90 = w^{2} + 5 w + 6

Switch sides

w^{2} + 5 w + 6 = 90

Move

90

to the left side

w^{2} + 5 w - 84 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 84 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 84) = 19

w_{1, 2} = \frac{- 5 \pm 19}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 5 + 19}{2 \cdot 1}, w_{2} = \frac{- 5 - 19}{2 \cdot 1}

w = \frac{- 5 + 19}{2 \cdot 1} : 7

w = \frac{- 5 - 19}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

w = 7, w = - 12

576 = 16 t^{2}

\frac{7 + 3}{7 - 3}

- 109 - 13 x = 47

\frac{2 x + 1}{7} - \frac{x}{3} = 3 - \frac{5 x + 9}{8}

\frac{1}{2} \cdot lo g_{3} (81)

What are the solutions to the equation 90=w^2+5w+6 ?
The solutions to the equation 90=w^2+5w+6 are w=7,w=-12
Find the zeros of 90=w^2+5w+6
The zeros of 90=w^2+5w+6 are w=7,w=-12