What are the solutions to the equation (-5x-1)(2x+8)=0 ?

The solutions to the equation (-5x-1)(2x+8)=0 are x=-1/5 ,x=-4

Find the zeros of (-5x-1)(2x+8)=0

The zeros of (-5x-1)(2x+8)=0 are x=-1/5 ,x=-4

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(- 5 x - 1) (2 x + 8) = 0

x = - \frac{1}{5}, x = - 4

Decimal Notation

x = - 0.2, x = - 4

Solution steps

(- 5 x - 1) (2 x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 5 x - 1 = 0 or 2 x + 8 = 0

Solve

- 5 x - 1 = 0 : x = - \frac{1}{5}

Solve

2 x + 8 = 0 : x = - 4

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - 4

(x + 9) (x - 9) = 0

y^{10}

s^{2} - s - 30 = 0

∣ 5 x - 1 ∣ \geq 5

What are the solutions to the equation (-5x-1)(2x+8)=0 ?
The solutions to the equation (-5x-1)(2x+8)=0 are x=-1/5 ,x=-4
Find the zeros of (-5x-1)(2x+8)=0
The zeros of (-5x-1)(2x+8)=0 are x=-1/5 ,x=-4