What are the solutions to the equation 63=(0.25^2-d^2)/(0.25^2)*100 ?

The solutions to the equation 63=(0.25^2-d^2)/(0.25^2)*100 are d=(sqrt(37))/(40),d=-(sqrt(37))/(40)

Find the zeros of 63=(0.25^2-d^2)/(0.25^2)*100

The zeros of 63=(0.25^2-d^2)/(0.25^2)*100 are d=(sqrt(37))/(40),d=-(sqrt(37))/(40)

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63 = \frac{0.2 5 ^{2} - d ^{2}}{0.2 5 ^{2}} \cdot 100

d = \frac{37}{40}, d = - \frac{37}{40}

Solution steps

63 = \frac{0.2 5 ^{2} - d ^{2}}{0.2 5 ^{2}} \cdot 100

Switch sides

\frac{0.2 5 ^{2} - d ^{2}}{0.2 5 ^{2}} \cdot 100 = 63

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{( 0.2 5 ^{2} - d ^{2} ) \cdot 100}{0.2 5 ^{2}} = 63

\frac{100 ( 0.2 5 ^{2} - d ^{2} )}{0.2 5 ^{2}} = 63

Multiply both sides by

0.2 5^{2}

0.2 5^{2} \cdot 100 - 100 d^{2} = 63 \cdot 0.2 5^{2}

Move

0.2 5^{2} \cdot 100

to the right side

- 100 d^{2} = - 2.3125

Divide both sides by

- 100

d^{2} = 0.023125

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 0.023125, d = - 0.023125

0.023125 = \frac{37}{40}

- 0.023125 = - \frac{37}{40}

d = \frac{37}{40}, d = - \frac{37}{40}

- \frac{π}{4} + 2 π

4 x + 12 = 171

6 - \frac{4}{2} (- 2.1451)^{2}

2 x^{2} - 3 = 0

i^{227}

What are the solutions to the equation 63=(0.25^2-d^2)/(0.25^2)*100 ?
The solutions to the equation 63=(0.25^2-d^2)/(0.25^2)*100 are d=(sqrt(37))/(40),d=-(sqrt(37))/(40)
Find the zeros of 63=(0.25^2-d^2)/(0.25^2)*100
The zeros of 63=(0.25^2-d^2)/(0.25^2)*100 are d=(sqrt(37))/(40),d=-(sqrt(37))/(40)