What are the solutions to the equation 2u^2-64=0 ?

The solutions to the equation 2u^2-64=0 are u=4sqrt(2),u=-4sqrt(2)

Find the zeros of 2u^2-64=0

The zeros of 2u^2-64=0 are u=4sqrt(2),u=-4sqrt(2)

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2 u^{2} - 64 = 0

u = 42, u = - 42

Decimal Notation

u = 5.65685 \dots, u = - 5.65685 \dots

Solution steps

2 u^{2} - 64 = 0

Move

64

to the right side

2 u^{2} = 64

Divide both sides by

2

u^{2} = 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = 32, u = - 32

32 = 42

- 32 = - 42

u = 42, u = - 42

\frac{3 \cdot 3 \cdot 3 \cdot 3 \cdot 3 \cdot 3}{3 \cdot 3 \cdot 3 \cdot 3}

2 k^{2} - 8 k - 90

0.594702 = 60 x - \frac{x ^{2} \cdot 60 \cdot \frac{60}{0.85 \cdot 4}}{2}

6 x + 24 - 3 x^{2}

(x + 4) (x + 1) > 0

What are the solutions to the equation 2u^2-64=0 ?
The solutions to the equation 2u^2-64=0 are u=4sqrt(2),u=-4sqrt(2)
Find the zeros of 2u^2-64=0
The zeros of 2u^2-64=0 are u=4sqrt(2),u=-4sqrt(2)