What is ((6-x))/(x+2)>1 ?

The solution to ((6-x))/(x+2)>1 is -2<x<2

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((6-x))/(x+2)>1

\frac{( 6 - x )}{x + 2} > 1

- 2 < x < 2

Interval Notation

(- 2, 2)

Solution steps

\frac{6 - x}{x + 2} > 1

Rewrite in standard form

\frac{- 2 x + 4}{x + 2} > 0

Factor

\frac{- 2 x + 4}{x + 2} : \frac{- 2 ( x - 2 )}{x + 2}

\frac{- 2 ( x - 2 )}{x + 2} > 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( x - 2 ) ) ( - 1 )}{x + 2} < 0 \cdot (- 1)

Simplify

\frac{2 ( x - 2 )}{x + 2} < 0

Divide both sides by

2

\frac{\frac{2 ( x - 2 )}{x + 2}}{2} < \frac{0}{2}

Simplify

\frac{x - 2}{x + 2} < 0

Identify the intervals

- 2 < x < 2

0.01 x + 0.1 x + 0.25 (48 - 2 x) = 3.42

4180

\frac{5}{4} + \frac{7}{8} + \frac{1}{16}

- \frac{1}{4} (4)^{2} + 4

- x^{2} + 12 x = 0