What are the solutions to the equation 2x^2-7x=0 ?

The solutions to the equation 2x^2-7x=0 are x= 7/2 ,x=0

Find the zeros of 2x^2-7x=0

The zeros of 2x^2-7x=0 are x= 7/2 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 7 x = 0

x = \frac{7}{2}, x = 0

Decimal Notation

x = 3.5, x = 0

Solution steps

2 x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 2}

x = \frac{- ( - 7 ) + 7}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 7 ) - 7}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 0

\frac{1}{1} - \frac{1}{2}

y^{2} - 11 y - 12

m^{2} - 2 m - 3 = 0

\frac{5}{9} - \frac{1}{2}

6 n^{2} + 72 n + 192

What are the solutions to the equation 2x^2-7x=0 ?
The solutions to the equation 2x^2-7x=0 are x= 7/2 ,x=0
Find the zeros of 2x^2-7x=0
The zeros of 2x^2-7x=0 are x= 7/2 ,x=0